Work smarter, not harder.

An empty gallon milk jug and a water hose. If you had done this to begin with, you'd already know.

Not trying to be an a$$, but sometimes the easiest route will get you what you need in the shortest amount of time.

 

Actually that would be way more time and effort having to get rid of contaminated water, drying out the tank, spendind money on additives to insure there is no contamination...... far from being smarter in my opinion.

But I appreciate the suggestion.

 

Really?!? Time and effort? Contamination? Flush the tank after letting it sit in the sunshine and fresh air for a few hours with some gas. It has been well over 24 hours and you still have no definate answer. How long and how much effort do you think it would take to do what I suggested?

Not going off on you in particular, but too many folks just want to ask a question and want the easier answer rather than use the grey matter that should be tucked between one's ears to figure things out on their own.

What you have asked is not rocket science. A simple Google search for the formula to figure out volume based on 3D measurements would have given you the answer being as the even simpler method of filling up the tank with your choice of a known amount of fluid is too much labor.

Just as a side note, your Algebra teacher in high school wasn't lying when they said that you would need it later in life.

 

I was going to suggest that when I first saw this post, but running through the numbers made me think twice before posting. Thanks to my favorite online conversion tool :

28-3/4" x 28-1/8" x 12-3/4"=10,309.570 cubic inch = 44.630 gallon

28-3/4" x 28-1/8" x 10-3/4"=8,692.383 cubic inch = 37.629 gallon

Clearly neither one of those comes close to what they should be. Maybe it has something to do with it being angled up on the bottom and the rounded edges. Or maybe it's because it's only suppose to be filled up to a certain point so fuel doesn't splash out. So simple algebra/geometry doesn't work in this situation, in fact, you'd have to use an integral that your calculus teacher taught you.

 

@ AJBert

Simple math is just that, simple.

The design of the tank does not allow your formula to work to arrive at an answer that is anywhere near what the specs allow for.

The whole idea of these forums is to share your vast knowlege, at least that is what I was told.

Please forgive my intrusion into this private domain of yours. It wont happen again.

 

This post has been bugging me. Why were my calculations so far off from what they should be? So I went to my garage and measured my 31 gallon tank that is removed from my Blazer - I got 27 x 26 5/8 x 11 3/4. Hmmm, seems like the LMC is actually posting the shipping dimensions because when I measured the lip around the perimeter it was 3/4".
So I did some calculations:

Volume of tank= 27x26.625x11.75 = 8446.78 cubic inches

But we need to remove some volume because the tank isn't exactly rectangular (angled portion on the bottom and the rounded corners)

Let's start with the prism shape we need to remove:
It's 1 5/8 high by 6 7/16 long (which means the hypotenuse is 6.639 - which we'll need later on).

Volume of prism= 1/2 x 1 5/8 x 6 7/16 x 26 5/8
or = .5 x 1.625 x 6.4375 x 26.625 = 139.26 cubic inches

Now we need to deal with the rounded edges:
The radius of the edges is 1.5 inches. If we take a snapshot of the profile of one of these edges it's a quarter circle. But the part we need to subtract isn't a quarter circle - it's the outside part of the quarter circle. Think of a quarter circle with radius 1.5 and then draw a square around that whose sides measure 1.5. We want to remove everything outside the quarter circle.

Area outside of quarter circle = (area of square) - (area of quarter circle)
or = (1.5 x 1.5) - 1/4(3.14 x 1.5.x 1.5)
= (2.25) - (1.77)
= 0.48 square inches

So for every linear inch of rounded edge around the tank we'll subtract 0.48 cubic inch

Adding up all the edges (this is where the hypotenuse comes into play) we get (if someone really wants me to explain where all these numbers came from I will but for simplicity sake I didn't include it):
(4 x 26.625) + (2 x 27) + (2 x 11.75 ) + (2 x 10.125) + (2 x 20.5625) + (2 x 6.639)

= 106.5 + 54 + 23.5 + 20.25 + 41.125 + 13.278
= 258.653 linear inches

So the volume we need to subtract for all the rounded edges is:
258.653 x 0.48 = 124.15344 cubic inches


The actual volume of the tank = 8446.78 - prism - edges
= 8446.78 - 139.26 - 124.15
= 8183.37 cubic inches

Now we know that 1 gallon = 231 cubic inches. Or we could just plug these numbers into my favorite online conversion site and find that the tank roughly holds 35.43 gallons. The level at which it actually holds 31 gallons is 1.42 inches below the top of the tank. Again, I think this is to help prevent fuel from splashing out if the rubber fill tube is faulty at that point.

So what I guess I'm trying to say is that you have a 31 gallon tank.

 

 

geea i wouklda just ran it to empty and went and filled it to thje top at the gas stattion it tells you how many gallons you filled up with

 

I think he needs to buy a sending unit, hard to do that without it.

 

i forgot what the originall question was haah everyone got wrapped up in tank sizes